(x^2+5x+3)-(-2x^2-3x-5)=0

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Solution for (x^2+5x+3)-(-2x^2-3x-5)=0 equation: 



(x^2+5x+3)-(-2x^2-3x-5)=0

We get rid of parentheses

2x^2+x^2+3x+5x+5+3=0

We add all the numbers together, and all the variables

3x^2+8x+8=0

a = 3; b = 8; c = +8;
Δ = b2-4ac
Δ = 82-4·3·8
Δ = -32
Delta is less than zero, so there is no solution for the equation

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